We will consider concepts and equipment primarily involved in handling and placing bulk material, namely earth.
Broad factors or characteristics to be considered:
Diesel engine characteristics:
~ less servicing, long life, less fuel used, fuel costs
~ less, lower fire hazard, less insurance premium, etc.
Equipment power unit mounting:
· batch plant (pg. 572, textbook)
· quarry crusher (pg. 530, textbook)
· tower crane (pg. 173, textbook)
· air compressor (pg. 332, textbook)
· separate propelling & performing engines
· integrated - same engine propels & performs
· crawler mounted (pg. 114, class notes)
· truck mounted (pg. 114, class notes)
tractors - track, wheel (pg. 97, 359, 361, textbook)
excavators - back hoes & front shovels (pg. 206, 213, 214, textbook)
~ Tracks (pg. 97 & 359, textbook)
flotation - low ground pressure
~ Wheels (pg. 97, 189 textbook)
Rolling resistance considerations:
~ varies with road surface type & condition.
~ rubber tires resistance also varies w/size, pressure & tread.
~soft earth increases a vehicles rolling resistance due to earth depressing.
~tire or track characteristics are best decided after road conditions are known.
~ haul road conditions change:
too dry, too wet, need maintenance & drainage
Rolling resistance for representative haul road conditions and different wheels or tracks are available (Table 4-2), pg. 73
Rolling resistance calculations (flat surface) (pg. 75, textbook):
~ R = rolling resistance (lb/ton) - Table 4-2, pg. 73 of your textbook
~ P = tension in tow cable (lb) - dynamometer test for total rolling resistance
~ W = gross weight of vehicle (tons)
~ R = P/W (for level haul road) - lbs. tractive pull per ton vehicle wt. moved
If other than for a level haul road, R must be corrected for the roads grade.
Grade resistance considerations:
~ varies with slope or grade of road
~ for down hill, grade resistance subtracts from rolling resistance (RR - GR)
~ for up hill, grade resistance adds to rolling resistance (RR + GR)
~ rule of thumb: (accurate up to 10% slope)
grade resistance force = 20 lb/ton/% grade (20 lbs. per gross ton of wt. for each 1% grade)
~ see Table 4-3 (pg. 75 of your textbook)
~ weight in tons is for the tractor plus any towed load
Total resistance (TR) (note: we will neglect wind resistance & acceleration):
~ TR = RR - GR (for down hill)
Grade resistance derivation: (also in textbook, pg 75)
Component of force to overcome to push [W] up the slope is W × sine "A".
For small "A" (A < 10°) sine A _ tangent A which = "A" expressed in radians.
F/W = sin A, F = W sin A = W tan A ;
F = W × tan A = 2,000 lb/ton × 1/100
Traction is the ability of drive wheels or tracks to transmit rimpull force to haul road surface.
Rubber tires on dry rough concrete have excellent traction, on wet sand have fair traction, and on ice have very poor traction.
A measure of this relative traction or slippage for varying surfaces is the coefficient of traction
Even though engine power is available, it will be nullified if sufficient traction cannot be developed.
Example in text: Rubber-tired tractor (see pg 78)
~ max. rimpull = 9,000 lb (low gear)
Tmax = W × Ct = 18,000 × 0.30 = 5,400 lb
here we can only use up to 5,400 lb of the 9,000 lb of avilable rimpull before experiencing loss of traction by slippage.
~ if Ct were 0.60 for a dry clay loam haul road:
Tmax = W × Ct = 18,000 × 0.60 = 10,800 lb
here the total available rimpull in low gear would be useful if needed.
Drawbar pull (engine pulling effort)
~ crawler tractors pull in pounds at its drawbar (pg. 77, textbook)
~ drawbar pull is engines pulling effort minus RR & GR
~ drawbar pull varies with gear speed
(see table, pgs. 73, 77, textbook)
~rubber tired vehicles tractive force (driving wheels on road surface) (pg. 85, textbook)
~ w/o slippage, rimpull depends on engine power & gear ratio
~ w/ slippage, effective rimpull is wt. on drivers times Ct
~ available rimpull formula: (see table, pg. 85, textbook)
~load pulling capability is rimpull minus RR & GR overcoming forces (see example, pg. 85, textbook)
Temperature & altitude have effects on engine horsepower.
Engines are rated at standard conditions:
~ 60°F; 29.92 inches hg (sea level pressure)
~ other temperatures & altitudes may be used
Engine hp decreases as temperature increases. HP
T
Engine hp decreases as altitude increases. HP
Alt.
(See Tables 4-5 & 4-6, pgs. 82 & 83 in textbook)
where: HPavail =horsepower available
Pactual =altitude at which the machine will be operated in inches Hg (inches of mercury) barometric pressure (see Table 4-6)
Pstd =standard condition altitude, usually sea level, 29.9 in. Hg
Tactual =Rankine temperature at which the machine will be operated
Tstd =standard condition temperature in Rankine units, usually 60°F, which equals 520°R
Factors determining actual fly wheel hp output
~ standard engine rated hp supplied
~ accessory load: fans, generators, compressors, A/C, etc.
~ load duration - without losing speed (normal accessories)
peak hp up to 5 minutes (W/1 5% engine hp)
continuous hp 8-24 hrs/day (_ 80% engine hp)
intermittent hp for < 1 hr (_ 90% engine hp)
From Table 4-6 observe rule of thumb (pg. 81, textbook)
~ 3% engine hp output/1000 ft altitude (loss due to altitude)
~ 1% engine hp output/10°F above 60°F (loss due to temperature)
~ 1% engine hp output/10°F below 60°F (loss due to temperature)
Example: A gasoline engine was tested under the given conditions and was found to develop the indicated horsepower. It is desired to convert the results to bhp (brake horsepower) for standard conditions.
Observed pressure, 29.52 in. Hg
Example: Rubber tired tractor scraper hauling fill
wt. distribution: 50% tractor, 50% scraper
~ Rubber tires mean work with rimpull. Assume sufficient hp.
|
RR |
% |
% |
Rimpull (lb) |
Re-sult |
||||
|
lb/ton/% |
Useable |
Required | ||||||
|
A |
120 |
6 |
2 |
Down |
4 |
18,750 |
10,000 |
OK |
|
B |
280 |
14 |
3 |
Up |
17 |
25,000 |
42,500 |
NG |
|
C |
80 |
4 |
2 |
Down |
2 |
100,000 |
5,000 |
OK |
useable rimpull = Wdrivers × Ct = .5 × 250,000 × Ct
required rimpull = Wtons × 20 lb/ton/% × TEG%
|
RR |
% |
% |
Rimpull (lb) |
Re-sult |
||||
|
lb/ton/% |
Useable |
Required | ||||||
|
A |
120 |
6 |
2 |
Up |
8 |
9,375 |
10,000 |
NG |
|
B |
280 |
14 |
3 |
Down |
11 |
12,500 |
13,750 |
NG |
|
C |
80 |
4 |
2 |
Up |
6 |
50,000 |
7,500 |
OK |
useable rimpull = Wdrivers × Ct = 62,500 Ct
required rimpull = Wtons × 20 × TEG
~For NG results we have a problem. We could use pusher, pave road, reduce the grade, change to track type prime mover, etc.
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